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Gleichungssysteme mit 4 Variablen
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Frage: Wie löse ich Gleichungssysteme
mit 3 oder mehr Variablen? |
Beispielaufgabe:
u + x + y + z = 10
- x + 2y = 3
- 2y + 3z = 5
4u - 3z = 7 |
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Zunächst
einmal ist es wichtig, die Variablen zu sortieren, d.h. die Aufgabe
so umzuwandeln, dass gleiche Variablen untereinander stehen, denn
ansonsten schleichen sich sehr leicht Fehler ein.
u |
+ |
x |
+ |
y |
+ |
z |
= |
10 |
Rechenanweisung: |
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- |
x |
+ |
2y |
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= |
3 |
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- |
2y |
+ |
3z |
= |
5 |
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4u |
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- |
3z |
= |
7 |
4 * I - IV -> IV |
(1. Schritt) |
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u |
+ |
x |
+ |
y |
+ |
z |
= |
10 |
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- |
x |
+ |
2y |
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= |
3 |
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- |
2y |
+ |
3z |
= |
5 |
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(2. Schritt) |
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4x |
+ |
4y |
+ |
7z |
= |
33 |
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u |
+ |
x |
+ |
y |
+ |
z |
= |
10 |
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- |
x |
+ |
2y |
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= |
3 |
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- |
2y |
+ |
3z |
= |
5 |
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12y |
+ |
7z |
= |
45 |
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(3. Schritt) |
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u |
+ |
x |
+ |
y |
+ |
z |
= |
10 |
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- |
x |
+ |
2y |
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= |
3 |
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- |
2y |
+ |
3z |
= |
5 |
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25z |
= |
75 |
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z |
= |
3 |
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- |
2y |
+ |
9 |
= |
5 |
/-9 |
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- |
2y |
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= |
-4 |
/-2 |
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y |
= |
2 |
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x |
+ |
4 |
= |
3 |
/-4 |
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- |
x |
= |
-1 |
/-2 |
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x |
= |
1 |
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u |
+ |
1 |
+ |
2 |
+ |
3 |
= |
10 |
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u |
+ |
6 |
= |
10 |
/-6 |
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u |
= |
4 |
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L |
= |
{(4/1/2/3)} |
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